What is the answer to solvefor b,c^2-5/2 b=2 ?

The answer to solvefor b,c^2-5/2 b=2 is b=-(4-2c^2)/5

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solvefor b,c^2-5/2 b=2

solve for

b, c^{2} - \frac{5}{2} b = 2

b = - \frac{4 - 2 c ^{2}}{5}

Solution steps

c^{2} - \frac{5}{2} b = 2

Move

c^{2}

to the right side

- \frac{5}{2} b = 2 - c^{2}

Multiply both sides by

2

- 5 b = 4 - 2 c^{2}

Divide both sides by

- 5

b = - \frac{4 - 2 c ^{2}}{5}

lo g_{10} (2) (9 x) - 4 lo g_{10} (2) (4) = 1

x, 3 (x - 1) + 2 y + 1 = 0

\frac{3 x}{4} + \frac{1}{2} = \frac{2 x - 3}{4}

\frac{4 x + 1}{2} = \frac{x - 5}{2}

\frac{2 x}{5} + \frac{3}{4} = \frac{1}{3} + \frac{x}{2}

What is the answer to solvefor b,c^2-5/2 b=2 ?
The answer to solvefor b,c^2-5/2 b=2 is b=-(4-2c^2)/5