What is the answer to (x+2)/2+(1-x)/3+(3x+1)/4 =2 ?

The answer to (x+2)/2+(1-x)/3+(3x+1)/4 =2 is x= 5/11

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(x+2)/2+(1-x)/3+(3x+1)/4 =2

\frac{x + 2}{2} + \frac{1 - x}{3} + \frac{3 x + 1}{4} = 2

x = \frac{5}{11}

Decimal Notation

x = 0.45454 \dots

Solution steps

\frac{x + 2}{2} + \frac{1 - x}{3} + \frac{3 x + 1}{4} = 2

Multiply by LCM

6 (x + 2) + 4 (- x + 1) + 3 (3 x + 1) = 24

Expand

6 (x + 2) + 4 (- x + 1) + 3 (3 x + 1) : 11 x + 19

11 x + 19 = 24

Move

19

to the right side

11 x = 5

Divide both sides by

11

x = \frac{5}{11}

x - 18 = 40

0.02 x + 0.04 = 0.18 - 0.05 x

5 x - 20 = 2 x + 10

F = 3 2^{2 5^{- 8^{- 3^{- 1}}}}

\frac{3 x - 3}{3} + \frac{4 x + 1}{2} = 0

What is the answer to (x+2)/2+(1-x)/3+(3x+1)/4 =2 ?
The answer to (x+2)/2+(1-x)/3+(3x+1)/4 =2 is x= 5/11
Solve for x: (x+2)/2+(1-x)/3+(3x+1)/4 =2
The solution is x= 5/11