What is the answer to (x-3)(x-7)=(x-3)(x+10) ?

The answer to (x-3)(x-7)=(x-3)(x+10) is x=3

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(x-3)(x-7)=(x-3)(x+10)

(x - 3) (x - 7) = (x - 3) (x + 10)

x = 3

Solution steps

(x - 3) (x - 7) = (x - 3) (x + 10)

Expand

(x - 3) (x - 7) : x^{2} - 10 x + 21

Expand

(x - 3) (x + 10) : x^{2} + 7 x - 30

x^{2} - 10 x + 21 = x^{2} + 7 x - 30

Move

21

to the right side

x^{2} - 10 x = x^{2} + 7 x - 51

Subtract

x^{2} + 7 x

from both sides

x^{2} - 10 x - (x^{2} + 7 x) = x^{2} + 7 x - 51 - (x^{2} + 7 x)

Simplify

- 17 x = - 51

Divide both sides by

- 17

x = 3

x, f^{- 1} (x) = 5 x

\frac{2 ( z - 8 )}{12} = \frac{3}{2}

x^{2} + 81 = x^{2} + 100

x, 3 x - 3 y = - 9

a, a + 2 b = 10

What is the answer to (x-3)(x-7)=(x-3)(x+10) ?
The answer to (x-3)(x-7)=(x-3)(x+10) is x=3
Solve for x: (x-3)(x-7)=(x-3)(x+10)
The solution is x=3