What is the answer to solvefor G,G(x)=(x+1)/(x^2+x-6) ?

The answer to solvefor G,G(x)=(x+1)/(x^2+x-6) is G=(x+1)/(x(x^2+x-6));\quad x\ne 0

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solvefor G,G(x)=(x+1)/(x^2+x-6)

solve for

G, G (x) = \frac{x + 1}{x ^{2} + x - 6}

G = \frac{x + 1}{x ( x ^{2} + x - 6 )}; x \neq = 0

Solution steps

G (x) = \frac{x + 1}{x ^{2} + x - 6}

Divide both sides by

x; x \neq = 0

G = \frac{x + 1}{x ( x ^{2} + x - 6 )}; x \neq = 0

6 - (4 + x) = 8 x - 2 (3 x + 5)

13 d - 28 = 8 + 12

\frac{2 ( x - 1 )}{3} = \frac{3 x + 6}{5}

x, \frac{x - 2 t}{a} = \frac{3 ( x - y )}{z}

\frac{4 x + 23}{5} = 3

What is the answer to solvefor G,G(x)=(x+1)/(x^2+x-6) ?
The answer to solvefor G,G(x)=(x+1)/(x^2+x-6) is G=(x+1)/(x(x^2+x-6));\quad x\ne 0