What is the answer to solvefor k,4(80+n)=(3k)n ?

The answer to solvefor k,4(80+n)=(3k)n is k=(4(80+n))/(3n);\quad n\ne 0

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solvefor k,4(80+n)=(3k)n

solve for

k, 4 (80 + n) = (3 k) n

k = \frac{4 ( 80 + n )}{3 n}; n \neq = 0

Solution steps

4 (80 + n) = (3 k) n

Switch sides

3 kn = 4 (80 + n)

Divide both sides by

n; n \neq = 0

3 k = \frac{4 ( 80 + n )}{n}; n \neq = 0

Divide both sides by

3; n \neq = 0

k = \frac{4 ( 80 + n )}{3 n}; n \neq = 0

\frac{1}{2} [1 + \frac{1}{4} (3 x - 1)] = \frac{2}{3} x - \frac{1}{2}

(3 x - 1)^{2} - (4 x + 3) (x - 7) - 2 = 1 + 5 (x^{2} - 2)

- 28 x + 6 = - 3 (1 + 7 x) - 7 x

0 = x + 7

x (0) = 0^{3}, y (0) = 0^{2}, 0 \leq 0 \leq 2

What is the answer to solvefor k,4(80+n)=(3k)n ?
The answer to solvefor k,4(80+n)=(3k)n is k=(4(80+n))/(3n);\quad n\ne 0