What are the solutions to the equation q^2+9q+20=0 ?

The solutions to the equation q^2+9q+20=0 are q=-4,q=-5

Find the zeros of q^2+9q+20=0

The zeros of q^2+9q+20=0 are q=-4,q=-5

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q^{2} + 9 q + 20 = 0

q = - 4, q = - 5

Solution steps

q^{2} + 9 q + 20 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

q_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 9 + 1}{2 \cdot 1}, q_{2} = \frac{- 9 - 1}{2 \cdot 1}

q = \frac{- 9 + 1}{2 \cdot 1} : - 4

q = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

q = - 4, q = - 5

- 24 = - 4 x

4 x - 3 = 13

4 t^{2} + 6 t + 3 = - 2 t

6 - 6 (3 - 2 x) < 5 (1 - x)

10 x + 1 > 8 x + 5

What are the solutions to the equation q^2+9q+20=0 ?
The solutions to the equation q^2+9q+20=0 are q=-4,q=-5
Find the zeros of q^2+9q+20=0
The zeros of q^2+9q+20=0 are q=-4,q=-5