What is the answer to 4+((40-x))/(130)-(13x)/(1932)=0 ?

The answer to 4+((40-x))/(130)-(13x)/(1932)=0 is x= 540960/1811

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4+((40-x))/(130)-(13x)/(1932)=0

4 + \frac{( 40 - x )}{130} - \frac{13 x}{1932} = 0

x = \frac{540960}{1811}

Decimal Notation

x = 298.70789 \dots

Solution steps

4 + \frac{( 40 - x )}{130} - \frac{13 x}{1932} = 0

4 + \frac{40 - x}{130} - \frac{13 x}{1932} = 0

Multiply by LCM

502320 + 966 (- x + 40) - 845 x = 0

Expand

502320 + 966 (- x + 40) - 845 x : - 1811 x + 540960

- 1811 x + 540960 = 0

Move

540960

to the right side

- 1811 x = - 540960

Divide both sides by

- 1811

x = \frac{540960}{1811}

x, x + y = 200

- 4 x + 13 + 6 x + 13 = 2

(4 x + 2) (4 x - 6) + 2 = 16 (x - 2)^{2} - 26

\frac{29}{18} + \frac{1}{2} x = - \frac{5}{3} (x + \frac{1}{3})

4 x - 3 + 2 x + 23 - x = 11 + 6 x + 19

What is the answer to 4+((40-x))/(130)-(13x)/(1932)=0 ?
The answer to 4+((40-x))/(130)-(13x)/(1932)=0 is x= 540960/1811
Solve for x: 4+((40-x))/(130)-(13x)/(1932)=0
The solution is x= 540960/1811