What are the solutions to the equation 4x^2+16x-9=0 ?

The solutions to the equation 4x^2+16x-9=0 are x= 1/2 ,x=-9/2

Find the zeros of 4x^2+16x-9=0

The zeros of 4x^2+16x-9=0 are x= 1/2 ,x=-9/2

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4 x^{2} + 16 x - 9 = 0

x = \frac{1}{2}, x = - \frac{9}{2}

Solution steps

4 x^{2} + 16 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 (- 9) = 20

x_{1, 2} = \frac{- 16 \pm 20}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 20}{2 \cdot 4}, x_{2} = \frac{- 16 - 20}{2 \cdot 4}

x = \frac{- 16 + 20}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 16 - 20}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{9}{2}

\frac{1}{2} \cdot π

\frac{8}{5 + i}

15 x^{2} + 2 x - 10 = 0

3 x^{2} - 2 x - 1 = 0

\frac{1}{12} + \frac{5}{6}

What are the solutions to the equation 4x^2+16x-9=0 ?
The solutions to the equation 4x^2+16x-9=0 are x= 1/2 ,x=-9/2
Find the zeros of 4x^2+16x-9=0
The zeros of 4x^2+16x-9=0 are x= 1/2 ,x=-9/2