What are the solutions to the equation 3x^2-2x-1=0 ?

The solutions to the equation 3x^2-2x-1=0 are x=1,x=-1/3

Find the zeros of 3x^2-2x-1=0

The zeros of 3x^2-2x-1=0 are x=1,x=-1/3

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3 x^{2} - 2 x - 1 = 0

x = 1, x = - \frac{1}{3}

Solution steps

3 x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 1) = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 3}

x = \frac{- ( - 2 ) + 4}{2 \cdot 3} : 1

x = \frac{- ( - 2 ) - 4}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{3}

\frac{1}{12} + \frac{5}{6}

(27 x^{6})^{\frac{2}{3}}

8 = \frac{3}{4} (5 x + 20)

\frac{1}{x ^{2} - 1} + 3 \geq 0

x^{- \frac{2}{3}}

What are the solutions to the equation 3x^2-2x-1=0 ?
The solutions to the equation 3x^2-2x-1=0 are x=1,x=-1/3
Find the zeros of 3x^2-2x-1=0
The zeros of 3x^2-2x-1=0 are x=1,x=-1/3