What is the answer to solvefor x,(λ-1)x+2y=0 ?

The answer to solvefor x,(λ-1)x+2y=0 is x=-(2y)/(λ-1);\quad λ\ne 1

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solvefor x,(λ-1)x+2y=0

solve for

x, (λ - 1) x + 2 y = 0

x = - \frac{2 y}{λ - 1}; λ \neq = 1

Solution steps

(λ - 1) x + 2 y = 0

Move

2 y

to the right side

(λ - 1) x = - 2 y

Divide both sides by

λ - 1; λ \neq = 1

x = - \frac{2 y}{λ - 1}; λ \neq = 1

2 \cdot (x + 1) = 4

n, \sum j = 1 n (3 j + 5 (j + 1) 2 - 3 j + 2 j^{2})

3 (72 m + 72) + 45 m = 3 (88 m - 50)

3 (x + 4) = 9 (2 x + 1) - 8 (3 x + 2)

\frac{x}{10} + \frac{1}{5} = \frac{3}{20}

What is the answer to solvefor x,(λ-1)x+2y=0 ?
The answer to solvefor x,(λ-1)x+2y=0 is x=-(2y)/(λ-1);\quad λ\ne 1