What are the solutions to the equation -3x+2=4x^2 ?

The solutions to the equation -3x+2=4x^2 are x=(-3+sqrt(41))/8 ,x=(-3-sqrt(41))/8

Find the zeros of -3x+2=4x^2

The zeros of -3x+2=4x^2 are x=(-3+sqrt(41))/8 ,x=(-3-sqrt(41))/8

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- 3 x + 2 = 4 x^{2}

x = \frac{- 3 + 41}{8}, x = \frac{- 3 - 41}{8}

Decimal Notation

x = 0.42539 \dots, x = - 1.17539 \dots

Solution steps

- 3 x + 2 = 4 x^{2}

Switch sides

4 x^{2} = - 3 x + 2

Move

2

to the left side

4 x^{2} - 2 = - 3 x

Move

3 x

to the left side

4 x^{2} - 2 + 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 2) = 41

x_{1, 2} = \frac{- 3 \pm 41}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 41}{2 \cdot 4}, x_{2} = \frac{- 3 - 41}{2 \cdot 4}

x = \frac{- 3 + 41}{2 \cdot 4} : \frac{- 3 + 41}{8}

x = \frac{- 3 - 41}{2 \cdot 4} : \frac{- 3 - 41}{8}

The solutions to the quadratic equation are:

x = \frac{- 3 + 41}{8}, x = \frac{- 3 - 41}{8}

\frac{x - 12}{8} \geq \frac{x - 6}{12} + \frac{5}{24}

8 - \frac{x}{9} = 6

x^{2} - 4 + x + 2 = 0

100 x^{2} - 9

(\frac{x}{3} - \frac{3 y}{2})^{2}

What are the solutions to the equation -3x+2=4x^2 ?
The solutions to the equation -3x+2=4x^2 are x=(-3+sqrt(41))/8 ,x=(-3-sqrt(41))/8
Find the zeros of -3x+2=4x^2
The zeros of -3x+2=4x^2 are x=(-3+sqrt(41))/8 ,x=(-3-sqrt(41))/8