What is the answer to g(r)=-1-7r,g(6) ?

The answer to g(r)=-1-7r,g(6) is g=(-1-7r)/r ;\quad \ne True for all r

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g(r)=-1-7r,g(6)

g (r) = - 1 - 7 r, g (6)

g = \frac{- 1 - 7 r}{r}; \neq = True for all r

Solution steps

g (r) = - 1 - 7 r

Divide both sides by

r; \neq =

True for all

r

g = \frac{- 1 - 7 r}{r}; \neq = True for all r

\frac{x}{5} + 5 = 15

\frac{1}{3} (2 + \frac{1}{5} (4 z - 1)) = \frac{3}{4} z - \frac{1}{3}

x, y = 2 x - 4

lo g_{5} (2 5^{4}) = 4

x, y - 5 x = 1

What is the answer to g(r)=-1-7r,g(6) ?
The answer to g(r)=-1-7r,g(6) is g=(-1-7r)/r ;\quad \ne True for all r