What are the solutions to the equation S^2-9S+6=0 ?

The solutions to the equation S^2-9S+6=0 are S=(9+sqrt(57))/2 ,S=(9-sqrt(57))/2

Find the zeros of S^2-9S+6=0

The zeros of S^2-9S+6=0 are S=(9+sqrt(57))/2 ,S=(9-sqrt(57))/2

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S^{2} - 9 S + 6 = 0

S = \frac{9 + 57}{2}, S = \frac{9 - 57}{2}

Decimal Notation

S = 8.27491 \dots, S = 0.72508 \dots

Solution steps

S^{2} - 9 S + 6 = 0

Solve with the quadratic formula

S_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 6 = 57

S_{1, 2} = \frac{- ( - 9 ) \pm 57}{2 \cdot 1}

Separate the solutions

S_{1} = \frac{- ( - 9 ) + 57}{2 \cdot 1}, S_{2} = \frac{- ( - 9 ) - 57}{2 \cdot 1}

S = \frac{- ( - 9 ) + 57}{2 \cdot 1} : \frac{9 + 57}{2}

S = \frac{- ( - 9 ) - 57}{2 \cdot 1} : \frac{9 - 57}{2}

The solutions to the quadratic equation are:

S = \frac{9 + 57}{2}, S = \frac{9 - 57}{2}

\frac{x}{2} + 3 = \frac{5 x}{3} - 4 x

∣ 3 + 2 x ∣ = 7

\frac{x ^{2} - x}{6} - \frac{x ^{2} + x}{3} = 0

∣ x + 5 ∣ > - 2

x^{2} - 16 x + 31 = 0

What are the solutions to the equation S^2-9S+6=0 ?
The solutions to the equation S^2-9S+6=0 are S=(9+sqrt(57))/2 ,S=(9-sqrt(57))/2
Find the zeros of S^2-9S+6=0
The zeros of S^2-9S+6=0 are S=(9+sqrt(57))/2 ,S=(9-sqrt(57))/2