What is the answer to R=(1+3i}{i(4-5i)}+2/i-\frac{1-3i)/6 ?

The answer to R=(1+3i}{i(4-5i)}+2/i-\frac{1-3i)/6 is R= 61/246-i 101/82

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R=(1+3i}{i(4-5i)}+2/i-\frac{1-3i)/6

R = \frac{1 + 3 i}{i ( 4 - 5 i )} + \frac{2}{i} - \frac{1 - 3 i}{6}

R = \frac{61}{246} - i \frac{101}{82}

Solution steps

R = \frac{1 + 3 i}{i ( 4 - 5 i )} + \frac{2}{i} - \frac{1 - 3 i}{6}

Simplify

\frac{1 + 3 i}{i ( 4 - 5 i )} + \frac{2}{i} - \frac{1 - 3 i}{6} : \frac{61}{246} - i \frac{101}{82}

R = \frac{61}{246} - i \frac{101}{82}

4 (x + 5) = 6 (2 x - 1)

n (3 n x + m) - m (1 - 3 m x) = n^{2} + m (n + m - 1)

\frac{1}{2} x + \frac{1}{4} - \frac{1}{10} x = \frac{1}{5}

y = 0 + 2

x, x (n) - 3 y (n - 1) - 2 y (n - 2) = 0

What is the answer to R=(1+3i}{i(4-5i)}+2/i-\frac{1-3i)/6 ?
The answer to R=(1+3i}{i(4-5i)}+2/i-\frac{1-3i)/6 is R= 61/246-i 101/82