What is the answer to [((c+2)^2)/2+(c+2)]-[((c)^2)/2+(c)]=8 ?

The answer to [((c+2)^2)/2+(c+2)]-[((c)^2)/2+(c)]=8 is c=2

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[((c+2)^2)/2+(c+2)]-[((c)^2)/2+(c)]=8

[\frac{( c + 2 ) ^{2}}{2} + (c + 2)] - [\frac{( c ) ^{2}}{2} + (c)] = 8

c = 2

Solution steps

[\frac{( c + 2 ) ^{2}}{2} + (c + 2)] - [\frac{c ^{2}}{2} + (c)] = 8

Expand

(\frac{( c + 2 ) ^{2}}{2} + (c + 2)) - (\frac{c ^{2}}{2} + (c)) : 2 c + 4

2 c + 4 = 8

Move

4

to the right side

2 c = 4

Divide both sides by

2

c = 2

\frac{d}{2} + 3 = 128

- 21 - 40 i + y = 2 (78 - 75 i)

w = (\frac{4}{3} 0.5)^{3}

2 x + 3 = - 3

(x - 4) (x - 3) = x^{2} + 2 x + 8

What is the answer to [((c+2)^2)/2+(c+2)]-[((c)^2)/2+(c)]=8 ?
The answer to [((c+2)^2)/2+(c+2)]-[((c)^2)/2+(c)]=8 is c=2
Solve for c: [((c+2)^2)/2+(c+2)]-[((c)^2)/2+(c)]=8
The solution is c=2