What is the answer to 1/7 [2-3(x+2)]= 1/5 [(-3x+1)+1/2 x] ?

The answer to 1/7 [2-3(x+2)]= 1/5 [(-3x+1)+1/2 x] is x= 54/5

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1/7 [2-3(x+2)]= 1/5 [(-3x+1)+1/2 x]

\frac{1}{7} [2 - 3 (x + 2)] = \frac{1}{5} [(- 3 x + 1) + \frac{1}{2} x]

x = \frac{54}{5}

Decimal Notation

x = 10.8

Solution steps

\frac{1}{7} [2 - 3 (x + 2)] = \frac{1}{5} [(- 3 x + 1) + \frac{1}{2} x]

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

\frac{1 \cdot ( 2 - 3 ( x + 2 ) )}{7} = \frac{1}{5} [(- 3 x + 1) + \frac{1}{2} x]

1 \cdot (2 - 3 (x + 2)) = 2 - 3 (x + 2)

\frac{2 - 3 ( x + 2 )}{7} = \frac{1}{5} [(- 3 x + 1) + \frac{1}{2} x]

Multiply by LCM

5 (- 3 (x + 2) + 2) = 7 (- \frac{5}{2} x + 1)

Expand

5 (- 3 (x + 2) + 2) : - 15 x - 20

Expand

7 (- \frac{5}{2} x + 1) : - \frac{35}{2} x + 7

- 15 x - 20 = - \frac{35}{2} x + 7

Multiply both sides by

2

- 30 x - 40 = - 35 x + 14

Move

40

to the right side

- 30 x = - 35 x + 54

Move

35 x

to the left side

5 x = 54

Divide both sides by

5

x = \frac{54}{5}

2 x + 1 = 4 (x - 6)

x, m (p x + q) = n

- 3 = 3 a + 6

3 (x + 5) - 7 (1 - x) = 8 (x - 4) - 2 (x + 1)

\frac{x + 1}{4} + \frac{x - 1}{2} = 2

What is the answer to 1/7 [2-3(x+2)]= 1/5 [(-3x+1)+1/2 x] ?
The answer to 1/7 [2-3(x+2)]= 1/5 [(-3x+1)+1/2 x] is x= 54/5
Solve for x: 1/7 [2-3(x+2)]= 1/5 [(-3x+1)+1/2 x]
The solution is x= 54/5