What is the answer to (z-1)^2+3=(z+1)^2-3 ?

The answer to (z-1)^2+3=(z+1)^2-3 is z= 3/2

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(z-1)^2+3=(z+1)^2-3

(z - 1)^{2} + 3 = (z + 1)^{2} - 3

z = \frac{3}{2}

Decimal Notation

z = 1.5

Solution steps

(z - 1)^{2} + 3 = (z + 1)^{2} - 3

Expand

(z - 1)^{2} + 3 : z^{2} - 2 z + 4

Expand

(z + 1)^{2} - 3 : z^{2} + 2 z - 2

z^{2} - 2 z + 4 = z^{2} + 2 z - 2

Move

4

to the right side

z^{2} - 2 z = z^{2} + 2 z - 6

Subtract

z^{2} + 2 z

from both sides

z^{2} - 2 z - (z^{2} + 2 z) = z^{2} + 2 z - 6 - (z^{2} + 2 z)

Simplify

- 4 z = - 6

Divide both sides by

- 4

z = \frac{3}{2}

2 (x + 1) = (x + 1) + 4

\frac{2 x - 5}{3} - \frac{3 x + 1}{4} = \frac{7 - x}{2}

lo g_{10} (450) = x

x = \frac{0 + 0 \cdot 5 + 4}{2 \cdot 5 ^{2}}

x, y - y^{0} = m (x - x^{0})

What is the answer to (z-1)^2+3=(z+1)^2-3 ?
The answer to (z-1)^2+3=(z+1)^2-3 is z= 3/2
Solve for z: (z-1)^2+3=(z+1)^2-3
The solution is z= 3/2