What is the answer to solvefor x,y-2=-2/3 (x-4) ?

The answer to solvefor x,y-2=-2/3 (x-4) is x=-(3y-6)/2+4

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solvefor x,y-2=-2/3 (x-4)

solve for

x, y - 2 = - \frac{2}{3} (x - 4)

x = - \frac{3 y - 6}{2} + 4

Solution steps

y - 2 = - \frac{2}{3} (x - 4)

Switch sides

- \frac{2}{3} (x - 4) = y - 2

Multiply both sides by

3

- 2 (x - 4) = 3 y - 6

Divide both sides by

- 2

x - 4 = - \frac{3 y - 6}{2}

Move

4

to the right side

x = - \frac{3 y - 6}{2} + 4

x, x^{2} + y^{2} + z^{2} + 2 x - 6 z + 9 = 0

d = (0 - (- 3))^{2} + (- 2 - (- 3))^{2}

4 + \frac{x}{3} = x

\frac{x}{3} + 4 x = 39

2 (5) - 7 (3) = - 11

What is the answer to solvefor x,y-2=-2/3 (x-4) ?
The answer to solvefor x,y-2=-2/3 (x-4) is x=-(3y-6)/2+4