What is the answer to (x-2)/2+x/3 =1-(4-x)/6 ?

The answer to (x-2)/2+x/3 =1-(4-x)/6 is x=2

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(x-2)/2+x/3 =1-(4-x)/6

\frac{x - 2}{2} + \frac{x}{3} = 1 - \frac{4 - x}{6}

x = 2

Solution steps

\frac{x - 2}{2} + \frac{x}{3} = 1 - \frac{4 - x}{6}

Multiply by LCM

3 (x - 2) + 2 x = 6 - (4 - x)

Expand

3 (x - 2) + 2 x : 5 x - 6

Expand

6 - (4 - x) : x + 2

5 x - 6 = x + 2

Move

6

to the right side

5 x = x + 8

Move

x

to the left side

4 x = 8

Divide both sides by

4

x = 2

40 x + 18 (x - 3) = 468

\frac{x - 1}{3} - \frac{x + 2}{12} = \frac{x - 2}{2}

y, 1 - y = x

3 t + \frac{1}{5} - 5 = \frac{1}{5} + 5 t

10 (5 x + 12) = 370

What is the answer to (x-2)/2+x/3 =1-(4-x)/6 ?
The answer to (x-2)/2+x/3 =1-(4-x)/6 is x=2
Solve for x: (x-2)/2+x/3 =1-(4-x)/6
The solution is x=2