What is the answer to solvefor x,m^2x+1=m(x+1) ?

The answer to solvefor x,m^2x+1=m(x+1) is x= 1/m ;\quad m\ne 0,m\ne 1

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solvefor x,m^2x+1=m(x+1)

solve for

x, m^{2} x + 1 = m (x + 1)

x = \frac{1}{m}; m \neq = 0, m \neq = 1

Solution steps

m^{2} x + 1 = m (x + 1)

Expand

m (x + 1) : m x + m

m^{2} x + 1 = m x + m

Move

1

to the right side

m^{2} x = m x + m - 1

Move

m x

to the left side

m^{2} x - m x = m - 1

Factor

m^{2} x - m x : m x (m - 1)

m x (m - 1) = m - 1

Divide both sides by

m (m - 1); m \neq = 0, m \neq = 1

x = \frac{1}{m}; m \neq = 0, m \neq = 1

- \frac{1}{4} = - \frac{1}{4} + \frac{1}{8} y

a, z = (a - 8) + (b - 2) i

x, - 3 x + y = 18

2.7927 = (1 - x) \cdot 0.4231 + 8.4739 x

24 = a_{0} (0 + 3) (0 + 4)

What is the answer to solvefor x,m^2x+1=m(x+1) ?
The answer to solvefor x,m^2x+1=m(x+1) is x= 1/m ;\quad m\ne 0,m\ne 1