What are the solutions to the equation 15x^2-3x=5x^2-1 ?

The solutions to the equation 15x^2-3x=5x^2-1 are x= 3/20+i(sqrt(31))/(20),x= 3/20-i(sqrt(31))/(20)

Find the zeros of 15x^2-3x=5x^2-1

The zeros of 15x^2-3x=5x^2-1 are x= 3/20+i(sqrt(31))/(20),x= 3/20-i(sqrt(31))/(20)

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15 x^{2} - 3 x = 5 x^{2} - 1

x = \frac{3}{20} + i \frac{31}{20}, x = \frac{3}{20} - i \frac{31}{20}

Solution steps

15 x^{2} - 3 x = 5 x^{2} - 1

Move

1

to the left side

15 x^{2} - 3 x + 1 = 5 x^{2}

Move

5 x^{2}

to the left side

10 x^{2} - 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 10 \cdot 1}{2 \cdot 10}

Simplify

(- 3)^{2} - 4 \cdot 10 \cdot 1 : 31 i

x_{1, 2} = \frac{- ( - 3 ) \pm 31 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 31 i}{2 \cdot 10}, x_{2} = \frac{- ( - 3 ) - 31 i}{2 \cdot 10}

x = \frac{- ( - 3 ) + 31 i}{2 \cdot 10} : \frac{3}{20} + i \frac{31}{20}

x = \frac{- ( - 3 ) - 31 i}{2 \cdot 10} : \frac{3}{20} - i \frac{31}{20}

The solutions to the quadratic equation are:

x = \frac{3}{20} + i \frac{31}{20}, x = \frac{3}{20} - i \frac{31}{20}

(\frac{5 p}{q ^{2}})^{- 3}

\frac{1}{3 x - 7} \geq \frac{4}{3 - 2 x}

x^{5} y^{3} - x^{2}

x^{3} > 4 x

4 x^{2} - 3 x - 4 = 0

What are the solutions to the equation 15x^2-3x=5x^2-1 ?
The solutions to the equation 15x^2-3x=5x^2-1 are x= 3/20+i(sqrt(31))/(20),x= 3/20-i(sqrt(31))/(20)
Find the zeros of 15x^2-3x=5x^2-1
The zeros of 15x^2-3x=5x^2-1 are x= 3/20+i(sqrt(31))/(20),x= 3/20-i(sqrt(31))/(20)