What are the solutions to the equation 5s^2=11s+12 ?

The solutions to the equation 5s^2=11s+12 are s=3,s=-4/5

Find the zeros of 5s^2=11s+12

The zeros of 5s^2=11s+12 are s=3,s=-4/5

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5 s^{2} = 11 s + 12

s = 3, s = - \frac{4}{5}

Decimal Notation

s = 3, s = - 0.8

Solution steps

5 s^{2} = 11 s + 12

Move

12

to the left side

5 s^{2} - 12 = 11 s

Move

11 s

to the left side

5 s^{2} - 12 - 11 s = 0

Write in the standard form

a x^{2} + b x + c = 0

5 s^{2} - 11 s - 12 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 5 ( - 12 )}{2 \cdot 5}

(- 11)^{2} - 4 \cdot 5 (- 12) = 19

s_{1, 2} = \frac{- ( - 11 ) \pm 19}{2 \cdot 5}

Separate the solutions

s_{1} = \frac{- ( - 11 ) + 19}{2 \cdot 5}, s_{2} = \frac{- ( - 11 ) - 19}{2 \cdot 5}

s = \frac{- ( - 11 ) + 19}{2 \cdot 5} : 3

s = \frac{- ( - 11 ) - 19}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

s = 3, s = - \frac{4}{5}

lo g_{2} (∣ x ∣) = 4

(x + 2) + (x - 1) = 0

2.25 x = x^{2} - 25

lo g_{11} (600) = 1.4

\frac{2}{n} (\frac{n !}{2 ^{n + 1}})

What are the solutions to the equation 5s^2=11s+12 ?
The solutions to the equation 5s^2=11s+12 are s=3,s=-4/5
Find the zeros of 5s^2=11s+12
The zeros of 5s^2=11s+12 are s=3,s=-4/5