What are the solutions to the equation x^2-2x=-4 ?

The solutions to the equation x^2-2x=-4 are x=1+sqrt(3)i,x=1-sqrt(3)i

Find the zeros of x^2-2x=-4

The zeros of x^2-2x=-4 are x=1+sqrt(3)i,x=1-sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 2 x = - 4

x = 1 + 3 i, x = 1 - 3 i

Solution steps

x^{2} - 2 x = - 4

Move

4

to the left side

x^{2} - 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 4 : 23 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1} : 1 + 3 i

x = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

x = 1 + 3 i, x = 1 - 3 i

- 2 x^{2} + x + 4 = 0

- 5 (4 x - 7) + 8 = 3 x

(2^{3})^{- 2}

3 (2 x + 5) + 33 \leq 0

\frac{2 x ^{4} y ^{2} \cdot y x ^{- 3}}{( 2 x ^{2} y ^{2} \cdot y x ^{- 1} ) ^{- 3}}

What are the solutions to the equation x^2-2x=-4 ?
The solutions to the equation x^2-2x=-4 are x=1+sqrt(3)i,x=1-sqrt(3)i
Find the zeros of x^2-2x=-4
The zeros of x^2-2x=-4 are x=1+sqrt(3)i,x=1-sqrt(3)i