What are the solutions to the equation 0=2x^2+8x-24 ?

The solutions to the equation 0=2x^2+8x-24 are x=2,x=-6

Find the zeros of 0=2x^2+8x-24

The zeros of 0=2x^2+8x-24 are x=2,x=-6

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0 = 2 x^{2} + 8 x - 24

x = 2, x = - 6

Solution steps

0 = 2 x^{2} + 8 x - 24

Switch sides

2 x^{2} + 8 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 24 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 24) = 16

x_{1, 2} = \frac{- 8 \pm 16}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 16}{2 \cdot 2}, x_{2} = \frac{- 8 - 16}{2 \cdot 2}

x = \frac{- 8 + 16}{2 \cdot 2} : 2

x = \frac{- 8 - 16}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

\frac{x + 10}{3} \geq 2 x

6 x + 3 + 3 x = 5 x - 9

- 4150 + 696

p^{2} + 5 p = 14

9 d - 9 = 3 d - 1.8

What are the solutions to the equation 0=2x^2+8x-24 ?
The solutions to the equation 0=2x^2+8x-24 are x=2,x=-6
Find the zeros of 0=2x^2+8x-24
The zeros of 0=2x^2+8x-24 are x=2,x=-6