What is -7f-5(-8f+10)<-4f-3-3 ?

The solution to -7f-5(-8f+10)<-4f-3-3 is f< 44/37

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-7f-5(-8f+10)<-4f-3-3

- 7 f - 5 (- 8 f + 10) < - 4 f - 3 - 3

f < \frac{44}{37}

Interval Notation

(- \infty, \frac{44}{37})

Decimal Notation

f < 1.18918 \dots

Solution steps

- 7 f - 5 (- 8 f + 10) < - 4 f - 3 - 3

Subtract the numbers:

- 3 - 3 = - 6

- 7 f - 5 (- 8 f + 10) < - 4 f - 6

Expand

- 5 (- 8 f + 10) : 40 f - 50

- 7 f + 40 f - 50 < - 4 f - 6

Add similar elements:

- 7 f + 40 f = 33 f

33 f - 50 < - 4 f - 6

Move

50

to the right side

33 f < - 4 f + 44

Move

4 f

to the left side

37 f < 44

Divide both sides by

37

f < \frac{44}{37}

a^{\frac{4}{3}} \cdot 2 a^{\frac{1}{2}}

\frac{x - 3}{2 x + 7} \geq 1

\frac{y}{2} \geq 2

r^{2} + 6 r + 13 = 0

2 x^{2} = 12 x - 5

What is -7f-5(-8f+10)<-4f-3-3 ?
The solution to -7f-5(-8f+10)<-4f-3-3 is f< 44/37