What are the solutions to the equation r^2+6r+13=0 ?

The solutions to the equation r^2+6r+13=0 are r=-3+2i,r=-3-2i

Find the zeros of r^2+6r+13=0

The zeros of r^2+6r+13=0 are r=-3+2i,r=-3-2i

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r^{2} + 6 r + 13 = 0

r = - 3 + 2 i, r = - 3 - 2 i

Solution steps

r^{2} + 6 r + 13 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

6^{2} - 4 \cdot 1 \cdot 13 : 4 i

r_{1, 2} = \frac{- 6 \pm 4 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 6 + 4 i}{2 \cdot 1}, r_{2} = \frac{- 6 - 4 i}{2 \cdot 1}

r = \frac{- 6 + 4 i}{2 \cdot 1} : - 3 + 2 i

r = \frac{- 6 - 4 i}{2 \cdot 1} : - 3 - 2 i

The solutions to the quadratic equation are:

r = - 3 + 2 i, r = - 3 - 2 i

2 x^{2} = 12 x - 5

x^{2} - 8 x - 4 = 0

(x) (1 \cdot 1 0^{- 4}) = (1 \cdot 1 0^{- 5}) (25)

7.5 3

3 x - 1 < 14

What are the solutions to the equation r^2+6r+13=0 ?
The solutions to the equation r^2+6r+13=0 are r=-3+2i,r=-3-2i
Find the zeros of r^2+6r+13=0
The zeros of r^2+6r+13=0 are r=-3+2i,r=-3-2i