What is the answer to (2x+3)-(x+4-2x)=5-(x+2) ?

The answer to (2x+3)-(x+4-2x)=5-(x+2) is x=1

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(2x+3)-(x+4-2x)=5-(x+2)

(2 x + 3) - (x + 4 - 2 x) = 5 - (x + 2)

x = 1

Solution steps

(2 x + 3) - (x + 4 - 2 x) = 5 - (x + 2)

Remove parentheses:

(a) = a

2 x + 3 - (x + 4 - 2 x) = 5 - (x + 2)

Simplify

x + 4 - 2 x : - x + 4

2 x + 3 - (- x + 4) = 5 - (x + 2)

Expand

2 x + 3 - (- x + 4) : 3 x - 1

Expand

5 - (x + 2) : - x + 3

3 x - 1 = - x + 3

Move

1

to the right side

3 x = - x + 4

Move

x

to the left side

4 x = 4

Divide both sides by

4

x = 1

\frac{6}{5} x - \frac{7}{12} = 3 x + \frac{2}{5}

\frac{2}{5} a + 3 = 23

x, 8 x - 6 y = 0

\frac{5 x + 1}{3} - \frac{( x + 1 ) ^{2}}{2} = 1 - \frac{x ^{2}}{2} + \frac{1}{6}

\frac{3 ( 5 - 3 x )}{- 4} = - 15

What is the answer to (2x+3)-(x+4-2x)=5-(x+2) ?
The answer to (2x+3)-(x+4-2x)=5-(x+2) is x=1
Solve for x: (2x+3)-(x+4-2x)=5-(x+2)
The solution is x=1