What is the answer to solvefor f,f(sqrt(x-1))=x^2+2x-3 ?

The answer to solvefor f,f(sqrt(x-1))=x^2+2x-3 is f=(x+3)sqrt(x-1);\quad x\ne 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor f,f(sqrt(x-1))=x^2+2x-3

solve for

f, f (x - 1) = x^{2} + 2 x - 3

f = (x + 3) x - 1; x \neq = 1

Solution steps

f (x - 1) = x^{2} + 2 x - 3

Divide both sides by

x - 1; x \neq = 1

f = (x + 3) x - 1; x \neq = 1

y = \frac{1}{3} (3)

y = \frac{1}{3} (0)

x, 9 x + 6.6 y = 71.4

- 2 x = - 3 x - 12

\frac{x + 1}{2} + \frac{2 x - 1}{4} + \frac{x + 2}{3} = 1

What is the answer to solvefor f,f(sqrt(x-1))=x^2+2x-3 ?
The answer to solvefor f,f(sqrt(x-1))=x^2+2x-3 is f=(x+3)sqrt(x-1);\quad x\ne 1