What is the answer to solvefor k,log_{10}(p)=log_{10}(c)-klog_{10}(w) ?

The answer to solvefor k,log_{10}(p)=log_{10}(c)-klog_{10}(w) is k=-log_{w}(p/c);\quad w\ne 1

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solvefor k,log_{10}(p)=log_{10}(c)-klog_{10}(w)

solve for

k, lo g_{10} (p) = lo g_{10} (c) - k lo g_{10} (w)

k = - lo g_{w} (\frac{p}{c}); w \neq = 1

Solution steps

lo g_{10} (p) = lo g_{10} (c) - k lo g_{10} (w)

Switch sides

lo g_{10} (c) - k lo g_{10} (w) = lo g_{10} (p)

Move

lo g_{10} (c)

to the right side

- k lo g_{10} (w) = lo g_{10} (p) - lo g_{10} (c)

Divide both sides by

- lo g_{10} (w); w \neq = 1

k = - lo g_{w} (\frac{p}{c}); w \neq = 1

a = \frac{\frac{64}{2187}}{( \frac{2}{3} ) ^{8}}

x, y = x p + p^{2}

i, x = sin (x)

- 8 (2 b + 8) + 7 = - 137

4 - 2 (x + 7) = 3 (x + 5)

What is the answer to solvefor k,log_{10}(p)=log_{10}(c)-klog_{10}(w) ?
The answer to solvefor k,log_{10}(p)=log_{10}(c)-klog_{10}(w) is k=-log_{w}(p/c);\quad w\ne 1