What is the answer to solvefor j,j(s)= 5/(s^4+1)+3/s ?

The answer to solvefor j,j(s)= 5/(s^4+1)+3/s is j=(5s+3(s^4+1))/(s^2(s^4+1));\quad s\ne 0

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solvefor j,j(s)= 5/(s^4+1)+3/s

solve for

j, j (s) = \frac{5}{s ^{4} + 1} + \frac{3}{s}

j = \frac{5 s + 3 ( s ^{4} + 1 )}{s ^{2} ( s ^{4} + 1 )}; s \neq = 0

Solution steps

j (s) = \frac{5}{s ^{4} + 1} + \frac{3}{s}

Divide both sides by

s; s \neq = 0

j = \frac{5 s + 3 ( s ^{2} + 2 s + 1 ) ( s ^{2} - 2 s + 1 )}{s ^{2} ( s ^{2} + 2 s + 1 ) ( s ^{2} - 2 s + 1 )}; s \neq = 0

Simplify

\frac{5 s + 3 ( s ^{2} + 2 s + 1 ) ( s ^{2} - 2 s + 1 )}{s ^{2} ( s ^{2} + 2 s + 1 ) ( s ^{2} - 2 s + 1 )} : \frac{5 s + 3 ( s ^{4} + 1 )}{s ^{2} ( s ^{4} + 1 )}

j = \frac{5 s + 3 ( s ^{4} + 1 )}{s ^{2} ( s ^{4} + 1 )}; s \neq = 0

A, f = A \neg B \neg B \neg + A B \neg C \neg + A BC

x = (5^{l o g_{6} (2)}) (5^{l o g_{6} (18)})

8 - 5 x = - 3 (2 x + 4)

2 x + y = y + 2 x

2 (x - 3 (x - 4 (x - (\frac{x}{8} + 1)))) = 1

What is the answer to solvefor j,j(s)= 5/(s^4+1)+3/s ?
The answer to solvefor j,j(s)= 5/(s^4+1)+3/s is j=(5s+3(s^4+1))/(s^2(s^4+1));\quad s\ne 0