What are the solutions to the equation x^2+2x+4=0 ?

The solutions to the equation x^2+2x+4=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of x^2+2x+4=0

The zeros of x^2+2x+4=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i

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x^{2} + 2 x + 4 = 0

x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

x^{2} + 2 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 4 : 23 i

x_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3 i}{2 \cdot 1}

x = \frac{- 2 + 2 3 i}{2 \cdot 1} : - 1 + 3 i

x = \frac{- 2 - 2 3 i}{2 \cdot 1} : - 1 - 3 i

The solutions to the quadratic equation are:

x = - 1 + 3 i, x = - 1 - 3 i

16 y - 8 (3 y - 2) = - 24

7 x^{2} + 24 x + 9

a^{2} - 2 a^{3} + 3 a^{4} - 4 a^{5} + 6 a^{6}

- (- 52 - 28) = (- 40 + t) - (- 40)

(\frac{1}{3} (3 x)^{- \frac{2}{3}} \cdot 3)^{2}

What are the solutions to the equation x^2+2x+4=0 ?
The solutions to the equation x^2+2x+4=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of x^2+2x+4=0
The zeros of x^2+2x+4=0 are x=-1+sqrt(3)i,x=-1-sqrt(3)i