What is the answer to -(-52-28)=(-40+t)-(-40) ?

The answer to -(-52-28)=(-40+t)-(-40) is t=80

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-(-52-28)=(-40+t)-(-40)

- (- 52 - 28) = (- 40 + t) - (- 40)

t = 80

Solution steps

- (- 52 - 28) = (- 40 + t) - (- 40)

Switch sides

(- 40 + t) - (- 40) = - (- 52 - 28)

Remove parentheses:

(- a) = - a, - (- a) = a

- 40 + t + 40 = - (- 52 - 28)

Group like terms

t - 40 + 40 = - (- 52 - 28)

- 40 + 40 = 0

t = - (- 52 - 28)

Subtract the numbers:

- 52 - 28 = - 80

t = - (- 80)

Apply rule

- (- a) = a

t = 80

(\frac{1}{3} (3 x)^{- \frac{2}{3}} \cdot 3)^{2}

z^{2} + ∣ z ∣ = 0

y^{2} - y - 6

(x - 6) (x - 2) = - 4

What is the answer to -(-52-28)=(-40+t)-(-40) ?
The answer to -(-52-28)=(-40+t)-(-40) is t=80
Solve for t: -(-52-28)=(-40+t)-(-40)
The solution is t=80