What is the answer to 3x-(7x-2)=(2-x)-(2x+1) ?

The answer to 3x-(7x-2)=(2-x)-(2x+1) is x=1

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3x-(7x-2)=(2-x)-(2x+1)

3 x - (7 x - 2) = (2 - x) - (2 x + 1)

x = 1

Solution steps

3 x - (7 x - 2) = (2 - x) - (2 x + 1)

3 x - (7 x - 2) = 2 - x - (2 x + 1)

Expand

3 x - (7 x - 2) : - 4 x + 2

Expand

2 - x - (2 x + 1) : - 3 x + 1

- 4 x + 2 = - 3 x + 1

Move

2

to the right side

- 4 x = - 3 x - 1

Move

3 x

to the left side

- x = - 1

Divide both sides by

- 1

x = 1

3 x - 12 = 6 (x - 12)

y = (- 4)^{2} - 6 (- 4) - 72

y + 3 - 2 \frac{y}{3} + \frac{y}{( 2 )} = \frac{4}{( 3 )} - 3 \frac{y}{2}

\frac{5 - ( - 1 )}{2} - 2 = \frac{1 - ( - 1 )}{2} - \frac{2 ( - 1 + 1 )}{3}

\frac{x}{5} - \frac{5 + x}{20} = \frac{7}{16}

What is the answer to 3x-(7x-2)=(2-x)-(2x+1) ?
The answer to 3x-(7x-2)=(2-x)-(2x+1) is x=1
Solve for x: 3x-(7x-2)=(2-x)-(2x+1)
The solution is x=1