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Popular >

sqrt(2k^2+17)-x=0

Solution

2 k^{2} + 17 - x = 0

Solution

x = 2 k^{2} + 17

Solution steps

2 k^{2} + 17 - x = 0

Move

2 k^{2} + 17

to the right side

- x = - 2 k^{2} + 17

Divide both sides by

- 1

x = 2 k^{2} + 17

Popular Examples

solvefor x,2x+5y+6z=40 solve for

x, 2 x + 5 y + 6 z = 40

(a+b)((a^2-b^2-ay)/(a-b))+by=2ab

(a + b) (\frac{a ^{2} - b ^{2} - a y}{a - b}) + b y = 2 ab

x=0.7*1500*1*10^{-6}

x = 0.7 \cdot 1500 \cdot 1 \cdot 1 0^{- 6}

a=(x^2+x+4)(x^2+x+5)-(x^2+x+3)(x^2+x+6)

a = (x^{2} + x + 4) (x^{2} + x + 5) - (x^{2} + x + 3) (x^{2} + x + 6)

-2(3)+20(-1)+30(2)=53

- 2 (3) + 20 (- 1) + 30 (2) = 53

Frequently Asked Questions (FAQ)

What is the answer to sqrt(2k^2+17)-x=0 ?
The answer to sqrt(2k^2+17)-x=0 is x=sqrt(2k^2+17)