What are the solutions to the equation 2x^2+8x=90 ?

The solutions to the equation 2x^2+8x=90 are x=5,x=-9

Find the zeros of 2x^2+8x=90

The zeros of 2x^2+8x=90 are x=5,x=-9

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2 x^{2} + 8 x = 90

x = 5, x = - 9

Solution steps

2 x^{2} + 8 x = 90

Move

90

to the left side

2 x^{2} + 8 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 90 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 90) = 28

x_{1, 2} = \frac{- 8 \pm 28}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 28}{2 \cdot 2}, x_{2} = \frac{- 8 - 28}{2 \cdot 2}

x = \frac{- 8 + 28}{2 \cdot 2} : 5

x = \frac{- 8 - 28}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

x = 5, x = - 9

12 0^{2}

(\frac{y ^{2}}{6} - \frac{3}{2 y ^{2}})^{2} + 1

1 \cdot 1 0^{- 3}

12 (x - 3) - 35 (2 x - 5) = 3 - 34 (2 x - 6)

14 x - 21 x^{2}

What are the solutions to the equation 2x^2+8x=90 ?
The solutions to the equation 2x^2+8x=90 are x=5,x=-9
Find the zeros of 2x^2+8x=90
The zeros of 2x^2+8x=90 are x=5,x=-9