What are the solutions to the equation 2x^2+16x-8=0 ?

The solutions to the equation 2x^2+16x-8=0 are x=2(sqrt(5)-2),x=-2(2+sqrt(5))

Find the zeros of 2x^2+16x-8=0

The zeros of 2x^2+16x-8=0 are x=2(sqrt(5)-2),x=-2(2+sqrt(5))

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2 x^{2} + 16 x - 8 = 0

x = 2 (5 - 2), x = - 2 (2 + 5)

Decimal Notation

x = 0.47213 \dots, x = - 8.47213 \dots

Solution steps

2 x^{2} + 16 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

1 6^{2} - 4 \cdot 2 (- 8) = 85

x_{1, 2} = \frac{- 16 \pm 8 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 16 + 8 5}{2 \cdot 2}, x_{2} = \frac{- 16 - 8 5}{2 \cdot 2}

x = \frac{- 16 + 8 5}{2 \cdot 2} : 2 (5 - 2)

x = \frac{- 16 - 8 5}{2 \cdot 2} : - 2 (2 + 5)

The solutions to the quadratic equation are:

x = 2 (5 - 2), x = - 2 (2 + 5)

- 6 x^{2} + 6 x - 162 = 0

12 w - 24 = 12

\frac{( 8 c d ^{3} ) ( - 3 c ^{4} )}{6 c ^{2} d} - 9 c^{3} d^{2}

x^{2} y + x^{4} y^{3}

9 = \frac{1}{2} (5 x + 6)

What are the solutions to the equation 2x^2+16x-8=0 ?
The solutions to the equation 2x^2+16x-8=0 are x=2(sqrt(5)-2),x=-2(2+sqrt(5))
Find the zeros of 2x^2+16x-8=0
The zeros of 2x^2+16x-8=0 are x=2(sqrt(5)-2),x=-2(2+sqrt(5))