What is the answer to 7-4[x-(2-3x)]=-5x-[6-2(x-2)] ?

The answer to 7-4[x-(2-3x)]=-5x-[6-2(x-2)] is x= 25/13

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7-4[x-(2-3x)]=-5x-[6-2(x-2)]

7 - 4 [x - (2 - 3 x)] = - 5 x - [6 - 2 (x - 2)]

x = \frac{25}{13}

Decimal Notation

x = 1.92307 \dots

Solution steps

7 - 4 [x - (2 - 3 x)] = - 5 x - [6 - 2 (x - 2)]

Expand

7 - 4 (x - (2 - 3 x)) : - 16 x + 15

Expand

- 5 x - (6 - 2 (x - 2)) : - 3 x - 10

- 16 x + 15 = - 3 x - 10

Move

15

to the right side

- 16 x = - 3 x - 25

Move

3 x

to the left side

- 13 x = - 25

Divide both sides by

- 13

x = \frac{25}{13}

x, 95 x + 23 y = 1

4.46 = m (0.0031) + b

y, 3 x - 4 y + 12 = 0

a, 2 b - a = 6

E = 3 6^{\circ} + \frac{π}{5}

What is the answer to 7-4[x-(2-3x)]=-5x-[6-2(x-2)] ?
The answer to 7-4[x-(2-3x)]=-5x-[6-2(x-2)] is x= 25/13
Solve for x: 7-4[x-(2-3x)]=-5x-[6-2(x-2)]
The solution is x= 25/13