What is the answer to 2x+3(-x^2-1)=-(3x^2+2(x-1)-3(x+2)) ?

The answer to 2x+3(-x^2-1)=-(3x^2+2(x-1)-3(x+2)) is x=11

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2x+3(-x^2-1)=-(3x^2+2(x-1)-3(x+2))

2 x + 3 (- x^{2} - 1) = - (3 x^{2} + 2 (x - 1) - 3 (x + 2))

x = 11

Solution steps

2 x + 3 (- x^{2} - 1) = - (3 x^{2} + 2 (x - 1) - 3 (x + 2))

Expand

3 (- x^{2} - 1) : - 3 x^{2} - 3

2 x - 3 x^{2} - 3 = - (3 x^{2} + 2 (x - 1) - 3 (x + 2))

Expand

- (3 x^{2} + 2 (x - 1) - 3 (x + 2)) : - 3 x^{2} + x + 8

2 x - 3 x^{2} - 3 = - 3 x^{2} + x + 8

Move

3

to the right side

2 x - 3 x^{2} = - 3 x^{2} + x + 11

Subtract

- 3 x^{2} + x

from both sides

2 x - 3 x^{2} - (- 3 x^{2} + x) = - 3 x^{2} + x + 11 - (- 3 x^{2} + x)

Simplify

x = 11

90 (x + \frac{1}{2}) - 100 x = 15

\frac{x}{7} = 12

2 x + 3 + 3 (x - 1) = 2 (x + 2)

x^{2} + 1 = (x + 1) (x + 1)

\frac{1}{2} x = - 4

What is the answer to 2x+3(-x^2-1)=-(3x^2+2(x-1)-3(x+2)) ?
The answer to 2x+3(-x^2-1)=-(3x^2+2(x-1)-3(x+2)) is x=11
Solve for x: 2x+3(-x^2-1)=-(3x^2+2(x-1)-3(x+2))
The solution is x=11