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Popular >

x^2+1=(x+1)(x+1)

Solution

x^{2} + 1 = (x + 1) (x + 1)

Solution

x = 0

Solution steps

x^{2} + 1 = (x + 1) (x + 1)

Expand

(x + 1) (x + 1) : x^{2} + 2 x + 1

x^{2} + 1 = x^{2} + 2 x + 1

Move

1

to the right side

x^{2} = x^{2} + 2 x

Subtract

x^{2} + 2 x

from both sides

x^{2} - (x^{2} + 2 x) = x^{2} + 2 x - (x^{2} + 2 x)

Simplify

- 2 x = 0

Divide both sides by

- 2

x = 0

Popular Examples

\frac{1}{2} x = - 4

-6x-4=-10x-16-10x-16

- 6 x - 4 = - 10 x - 16 - 10 x - 16

solvefor x,(x-4)/3 =(y-8)/(-4)solve for

x, \frac{x - 4}{3} = \frac{y - 8}{- 4}

solvefor x,xy-2/3 x+13y-26/3 =260 solve for

x, x y - \frac{2}{3} x + 13 y - \frac{26}{3} = 260

\frac{1}{4} x + \frac{1}{2} x = 6

Frequently Asked Questions (FAQ)

What is the answer to x^2+1=(x+1)(x+1) ?
The answer to x^2+1=(x+1)(x+1) is x=0
Solve for x: x^2+1=(x+1)(x+1)
The solution is x=0