What is factor x^3+6x^2+12x+16 ?

The solution to factor x^3+6x^2+12x+16 is (x+4)(x^2+2x+4)

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factor x^3+6x^2+12x+16

factor

x^{3} + 6 x^{2} + 12 x + 16

(x + 4) (x^{2} + 2 x + 4)

Solution steps

x^{3} + 6 x^{2} + 12 x + 16

Use the rational root theorem

= (x + 4) \frac{x ^{3} + 6 x ^{2} + 12 x + 16}{x + 4}

\frac{x ^{3} + 6 x ^{2} + 12 x + 16}{x + 4} = x^{2} + 2 x + 4

= (x + 4) (x^{2} + 2 x + 4)

(a^{- 1})^{- 1}

\frac{( ( x - 3 ) ( x + 1 ) + 7 )}{( x - 4 )}

a^{12} - b^{12}

(11 a^{16} b^{3}) (\frac{4 a ^{3} b ^{6}}{c ^{8}})^{- 5}

x^{2} - 4 x + 4 y - y^{2}

What is factor x^3+6x^2+12x+16 ?
The solution to factor x^3+6x^2+12x+16 is (x+4)(x^2+2x+4)