What is ((3x^3-3x^2))/((x^3-x)) ?

The solution to ((3x^3-3x^2))/((x^3-x)) is (3x)/(x+1)

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simplify ((3x^3-3x^2))/((x^3-x))

simplify

\frac{( 3 x ^{3} - 3 x ^{2} )}{( x ^{3} - x )}

\frac{3 x}{x + 1}

Solution steps

\frac{3 x ^{3} - 3 x ^{2}}{x ^{3} - x}

Factor

3 x^{3} - 3 x^{2} : 3 x^{2} (x - 1)

= \frac{3 x ^{2} ( x - 1 )}{x ^{3} - x}

Factor

x^{3} - x : x (x + 1) (x - 1)

= \frac{3 x ^{2} ( x - 1 )}{x ( x + 1 ) ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{3 x ^{2}}{x ( x + 1 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{3 xx}{x ( x + 1 )}

Cancel the common factor:

x

= \frac{3 x}{x + 1}

3 x^{2} + 2 x^{3} + 8 x - 5 x y

(- 3 a^{2} b^{2}) (4 a^{5} b^{3})^{3}

(9 x - 7 y)^{3}

p^{8} + p^{4} + 1

(2 x^{2} + 6 y) 3

What is ((3x^3-3x^2))/((x^3-x)) ?
The solution to ((3x^3-3x^2))/((x^3-x)) is (3x)/(x+1)