What is expand (1+x)(1+x^2)(1+x^4)(1+x^8)(1-x) ?

The solution to expand (1+x)(1+x^2)(1+x^4)(1+x^8)(1-x) is 1-x^{16}

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expand (1+x)(1+x^2)(1+x^4)(1+x^8)(1-x)

expand

(1 + x) (1 + x^{2}) (1 + x^{4}) (1 + x^{8}) (1 - x)

1 - x^{16}

Solution steps

(1 + x) (1 + x^{2}) (1 + x^{4}) (1 + x^{8}) (1 - x)

Expand

(1 + x) (1 + x^{2}) (1 + x^{4}) (1 + x^{8}) (1 - x) : (1 - x^{2}) (1 + x^{2}) (1 + x^{4}) (1 + x^{8})

= (1 - x^{2}) (1 + x^{2}) (1 + x^{4}) (1 + x^{8})

Apply Difference of Two Squares

(1 - x^{2}) (1 + x^{2}) : 1 - x^{4}

= (1 - x^{4}) (1 + x^{4}) (1 + x^{8})

Apply Difference of Two Squares

(1 - x^{4}) (1 + x^{4}) : 1 - x^{8}

= (1 - x^{8}) (1 + x^{8})

Apply Difference of Two Squares

(1 - x^{8}) (1 + x^{8}) : 1 - x^{16}

= 1 - x^{16}

(b + 1)^{3}

- 1^{n}

1 - 64 y^{6}

16 m^{4} - 25 m^{2} \cdot n^{2} + 9 n^{4}

8 x^{3} + 3^{3}

What is expand (1+x)(1+x^2)(1+x^4)(1+x^8)(1-x) ?
The solution to expand (1+x)(1+x^2)(1+x^4)(1+x^8)(1-x) is 1-x^{16}