What is factor 125x^3-216-450x^2+540x ?

The solution to factor 125x^3-216-450x^2+540x is (5x-6)^3

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factor 125x^3-216-450x^2+540x

factor

125 x^{3} - 216 - 450 x^{2} + 540 x

(5 x - 6)^{3}

Solution steps

125 x^{3} - 216 - 450 x^{2} + 540 x

Write in the standard form

= 125 x^{3} - 450 x^{2} + 540 x - 216

Use the rational root theorem

= (5 x - 6) \frac{125 x ^{3} - 450 x ^{2} + 540 x - 216}{5 x - 6}

\frac{125 x ^{3} - 450 x ^{2} + 540 x - 216}{5 x - 6} = 25 x^{2} - 60 x + 36

= (5 x - 6) (25 x^{2} - 60 x + 36)

Factor

25 x^{2} - 60 x + 36 : (5 x - 6) (5 x - 6)

= (5 x - 6) (5 x - 6) (5 x - 6)

Apply exponent rule:

aaa = a^{3}

(5 x - 6) (5 x - 6) (5 x - 6) = (5 x - 6)^{3}

= (5 x - 6)^{3}

sin (x) + sin^{2} (x) + sin^{3} (x)

a \cdot b^{7} + b \cdot a^{7}

l^{- 1} \cdot {lo g_{10} (\frac{( s + 1 )}{( s - 1 )})}

\frac{1}{3} \cdot (\frac{1}{( 3 n - 1 )} - \frac{1}{( 3 n + 2 )})

(2 m - 5)^{3}

What is factor 125x^3-216-450x^2+540x ?
The solution to factor 125x^3-216-450x^2+540x is (5x-6)^3