What is f(x)+h(x)3x^3+5x^2-2x+7+x^4-2x^3+8x-14 ?

The solution to f(x)+h(x)3x^3+5x^2-2x+7+x^4-2x^3+8x-14 is fx+x^4-2x^3+5x^2+6x+3x^4h-7

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simplify f(x)+h(x)3x^3+5x^2-2x+7+x^4-2x^3+8x-14

simplify

f (x) + h (x) 3 x^{3} + 5 x^{2} - 2 x + 7 + x^{4} - 2 x^{3} + 8 x - 14

f x + x^{4} - 2 x^{3} + 5 x^{2} + 6 x + 3 x^{4} h - 7

Solution steps

f (x) + h (x) \cdot 3 x^{3} + 5 x^{2} - 2 x + 7 + x^{4} - 2 x^{3} + 8 x - 14

Group like terms

= f x + x^{4} - 2 x^{3} + 5 x^{2} - 2 x + 8 x + h x \cdot 3 x^{3} + 7 - 14

Add similar elements:

- 2 x + 8 x = 6 x

= f x + x^{4} - 2 x^{3} + 5 x^{2} + 6 x + h x \cdot 3 x^{3} + 7 - 14

Subtract the numbers:

7 - 14 = - 7

= f x + x^{4} - 2 x^{3} + 5 x^{2} + 6 x + h x \cdot 3 x^{3} - 7

Simplify

h x \cdot 3 x^{3} : 3 x^{4} h

= f x + x^{4} - 2 x^{3} + 5 x^{2} + 6 x + 3 x^{4} h - 7

14 x^{3} + 9 x^{2} - 4

\frac{( 18 x + 15 )}{3}

a^{3} - \frac{1}{( a ^{3} )} - 2 a + \frac{2}{a}

\frac{( x ^{2} - 2 x - 3 )}{( x - 3 )}

tan (x) sin (x) + sec (x) cos^{2} (x)

What is f(x)+h(x)3x^3+5x^2-2x+7+x^4-2x^3+8x-14 ?
The solution to f(x)+h(x)3x^3+5x^2-2x+7+x^4-2x^3+8x-14 is fx+x^4-2x^3+5x^2+6x+3x^4h-7