What is (2r^{-3})(2r^0) ?

The solution to (2r^{-3})(2r^0) is 4/(r^3)

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simplify (2r^{-3})(2r^0)

simplify

(2 r^{- 3}) (2 r^{0})

\frac{4}{r ^{3}}

Solution steps

(2 r^{- 3}) (2 r^{0})

Simplify

2 r^{- 3} : \frac{2}{r ^{3}}

= \frac{2}{r ^{3}} \cdot 2 r^{0}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

r^{0} = 1

= \frac{2}{r ^{3}} \cdot 2 \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= \frac{2}{r ^{3}} \cdot 2

= 2 \cdot \frac{2}{r ^{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 2}{r ^{3}}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{4}{r ^{3}}

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(x + 1)^{20}