What are the solutions to the equation p^2-5p+4=0 ?

The solutions to the equation p^2-5p+4=0 are p=4,p=1

Find the zeros of p^2-5p+4=0

The zeros of p^2-5p+4=0 are p=4,p=1

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p^{2} - 5 p + 4 = 0

p = 4, p = 1

Solution steps

p^{2} - 5 p + 4 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

p_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, p_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

p = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

p = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

p = 4, p = 1

x^{2} (x - 4) < 0

r^{2} + 18 r + 81 = 0

- 2 x^{2} - 11 x - 15

w^{2} = 7 (w - 6)

- 3 t + 9 \geq - 21

What are the solutions to the equation p^2-5p+4=0 ?
The solutions to the equation p^2-5p+4=0 are p=4,p=1
Find the zeros of p^2-5p+4=0
The zeros of p^2-5p+4=0 are p=4,p=1