What are the solutions to the equation r^2+18r+81=0 ?

The solutions to the equation r^2+18r+81=0 are r=-9

Find the zeros of r^2+18r+81=0

The zeros of r^2+18r+81=0 are r=-9

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r^{2} + 18 r + 81 = 0

r = - 9

Solution steps

r^{2} + 18 r + 81 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 81 = 0

r_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 1}

r = \frac{- 18}{2 \cdot 1}

\frac{- 18}{2 \cdot 1} = - 9

r = - 9

The solution to the quadratic equation is:

r = - 9

- 2 x^{2} - 11 x - 15

w^{2} = 7 (w - 6)

- 3 t + 9 \geq - 21

7 x^{2} y - 27 x y^{2} + 18 y^{3}

r^{2} - 2 r + 2 = 0

What are the solutions to the equation r^2+18r+81=0 ?
The solutions to the equation r^2+18r+81=0 are r=-9
Find the zeros of r^2+18r+81=0
The zeros of r^2+18r+81=0 are r=-9