What is (b-2019)/(10-2001-12) ?

The solution to (b-2019)/(10-2001-12) is -(b-2019)/(2003)

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simplify (b-2019)/(10-2001-12)

simplify

\frac{b - 2019}{10 - 2001 - 12}

- \frac{b - 2019}{2003}

Solution steps

\frac{b - 2019}{10 - 2001 - 12}

Subtract the numbers:

10 - 2001 - 12 = - 2003

= \frac{b - 2019}{- 2003}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{b - 2019}{2003}

3 x^{2} - 5 x y + 2 y^{2}

(x + y + 2)^{3}

9 x^{2} - 6 b^{2} x - (a^{4} - b^{4})

\frac{( \frac{4}{( x ^{2} - 7 x + 12 )} ) + 3}{( 3 - x )}

79 x^{12} + 12 - 60 x^{12}

What is (b-2019)/(10-2001-12) ?
The solution to (b-2019)/(10-2001-12) is -(b-2019)/(2003)