What is factor 16a^4-4a^2+4a-1 ?

The solution to factor 16a^4-4a^2+4a-1 is (4a^2+2a-1)(4a^2-2a+1)

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factor 16a^4-4a^2+4a-1

factor

16 a^{4} - 4 a^{2} + 4 a - 1

(4 a^{2} + 2 a - 1) (4 a^{2} - 2 a + 1)

Solution steps

16 a^{4} - 4 a^{2} + 4 a - 1

Factor

- 4 a^{2} + 4 a - 1 : - (2 a - 1)^{2}

= 16 a^{4} - (2 a - 1)^{2}

Simplify

16 a^{4} : (4 a^{2})^{2}

= (4 a^{2})^{2} - (2 a - 1)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 a^{2})^{2} - (2 a - 1)^{2} = (4 a^{2} + (2 a - 1)) (4 a^{2} - (2 a - 1))

= (4 a^{2} + (2 a - 1)) (4 a^{2} - (2 a - 1))

Simplify

(4 a^{2} + (2 a - 1)) (4 a^{2} - (2 a - 1)) : (4 a^{2} + 2 a - 1) (4 a^{2} - 2 a + 1)

= (4 a^{2} + 2 a - 1) (4 a^{2} - 2 a + 1)

3 m^{4} - 8 m^{2} - 16

sin (a) cos (a) (tan^{2} (a) + cot^{2} (x))

\frac{( 2 a ) ^{3}}{2 a ^{2}}

x^{3} + 3 x^{2} + 3 x + 28

\frac{( x ^{4} - 9 )}{( x ^{2} + 3 )}

What is factor 16a^4-4a^2+4a-1 ?
The solution to factor 16a^4-4a^2+4a-1 is (4a^2+2a-1)(4a^2-2a+1)