What is factor x^3+3x^2+3x+28 ?

The solution to factor x^3+3x^2+3x+28 is (x+4)(x^2-x+7)

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factor x^3+3x^2+3x+28

factor

x^{3} + 3 x^{2} + 3 x + 28

(x + 4) (x^{2} - x + 7)

Solution steps

x^{3} + 3 x^{2} + 3 x + 28

Use the rational root theorem

= (x + 4) \frac{x ^{3} + 3 x ^{2} + 3 x + 28}{x + 4}

\frac{x ^{3} + 3 x ^{2} + 3 x + 28}{x + 4} = x^{2} - x + 7

= (x + 4) (x^{2} - x + 7)

\frac{( x ^{4} - 9 )}{( x ^{2} + 3 )}

x^{2} + \frac{x}{6} - \frac{1}{6}

- x^{2} + \frac{1}{( x ^{2} )} + 2 - 2 x - \frac{2}{x}

12 x^{2} \cdot y + 6 x \cdot y^{3}

5 y x^{2} y

What is factor x^3+3x^2+3x+28 ?
The solution to factor x^3+3x^2+3x+28 is (x+4)(x^2-x+7)